X^2-4x-148=0

Solution for X^2-4x-148=0 equation:

X^2-4X-148=0

a = 1; b = -4; c = -148;
Δ = b2-4ac
Δ = -42-4·1·(-148)
Δ = 608
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{608}=\sqrt{16*38}=\sqrt{16}*\sqrt{38}=4\sqrt{38}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{38}}{2*1}=\frac{4-4\sqrt{38}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{38}}{2*1}=\frac{4+4\sqrt{38}}{2}
$